(3y^2-3y+2)+(4y^2+3y-1)=0

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Solution for (3y^2-3y+2)+(4y^2+3y-1)=0 equation:


Simplifying
(3y2 + -3y + 2) + (4y2 + 3y + -1) = 0

Reorder the terms:
(2 + -3y + 3y2) + (4y2 + 3y + -1) = 0

Remove parenthesis around (2 + -3y + 3y2)
2 + -3y + 3y2 + (4y2 + 3y + -1) = 0

Reorder the terms:
2 + -3y + 3y2 + (-1 + 3y + 4y2) = 0

Remove parenthesis around (-1 + 3y + 4y2)
2 + -3y + 3y2 + -1 + 3y + 4y2 = 0

Reorder the terms:
2 + -1 + -3y + 3y + 3y2 + 4y2 = 0

Combine like terms: 2 + -1 = 1
1 + -3y + 3y + 3y2 + 4y2 = 0

Combine like terms: -3y + 3y = 0
1 + 0 + 3y2 + 4y2 = 0
1 + 3y2 + 4y2 = 0

Combine like terms: 3y2 + 4y2 = 7y2
1 + 7y2 = 0

Solving
1 + 7y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7y2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 7y2 = 0 + -1
7y2 = 0 + -1

Combine like terms: 0 + -1 = -1
7y2 = -1

Divide each side by '7'.
y2 = -0.1428571429

Simplifying
y2 = -0.1428571429

Reorder the terms:
0.1428571429 + y2 = -0.1428571429 + 0.1428571429

Combine like terms: -0.1428571429 + 0.1428571429 = 0.0000000000
0.1428571429 + y2 = 0.0000000000

The solution to this equation could not be determined.

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